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43w+63+4w^2=0
a = 4; b = 43; c = +63;
Δ = b2-4ac
Δ = 432-4·4·63
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-29}{2*4}=\frac{-72}{8} =-9 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+29}{2*4}=\frac{-14}{8} =-1+3/4 $
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